I'm wondering this in general, but for this post I'll ask about the E50 from Puch, as that's the wiring diagram I'm looking at (https://www.mopedarmy.com/w/images/b/bb/Stock_puch_wiring_diagram.jpg).
I drew it out as a modified version, and essentially I'd be replacing the stock 6V lighting coil with a 12V lighting coil, and off of that I'd run it directly into a rectifier and then a 14~ish volt regulator for charging a 12V battery (I might need a dedicated charging circuit between here though), and then off the battery I'd have one more 12V reg going to all my lights, a new horn, signals, etc.
So my questions are as follows:
How does one go about replacing a lighting coil? I know that's vague but in this example a puch e50 diagram is pretty simple, but the wires coming off the generator are unclear. It's not really revealed which coil even is the lighting coil.
Would I need some sort of dedicated battery charging circuit after a 12V reg/rectifier? If so, can you link me something?
On treats, https://www.treatland.tv/puch-12-volt-light-coil-2-0-improved-version-p/puch-light-coil.htm this coil seems like a good point of reference. The review says that only one of the rails really matters, as the headlight cable will power everything sufficiently. I just need it to get fed into a couple of components and then a battery. So is it safe to assume that this would get wired up yellow wire (12V AC) to the positive input of a rectifier/regulator, and then it would share an AC ground with the ignition coil (meaning the brown wire on the diagram would go into the negative input of the rectifier/regulator)? (edited)